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Calculate the pressure exterted by liquid having a density of 13600 kg/m3 and a depth of 12 meter.

User Ragini
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The density of the liquid is,


d=13600kg/m^3

The depth is,


h=12\text{ m}

The pressure at any depth for a liquid is given by,


P=\text{hdg}

Substituting the values we get,


\begin{gathered} P=12*13600*9.8 \\ =1.599*10^6N/m^2 \end{gathered}

The required pressure at that depth is,


1.599*10^6N/m^2

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