Question

Instructions: Find the equation of the line through point (1, -5) and perpendicular to y = 1 + 2. Use a forward slash (ie, "/") for fractions (e.g. 1/2 for 5)

Answer 1

First we know that the new line is perpendicular to:

`y=(1)/(8)x+2`

So our new slope will be the negative reciproc of the slope so

`m=-8`

Now we can replace the coordinate in our new equation to find b so:

`\begin{gathered} y=-8x+b \\ -5=-8(1)+b \\ b=8-5 \\ b=3 \end{gathered}`

So the final equation is:

`y=-8x+3`