Question

You have a line AB where A is (0,3) and Bis (3,9) find a point P that partitions the line 1:2.

Answer 1

If a line with coordinates (x1, y1) and (x2, y2) is partitioned at point P in a ratio a:b, point P is located at:

`(x_1+(a)/(a+b)(x_2-x_1),y_1+(a)/(a+b)(y_2-y_1))`

In this case, the points are A(0,3) and B(3,9), and the ratio is 1:2, then P is located at:

`\begin{gathered} (0+(1)/(1+2)(3-0),3+(1)/(1+2)(9-3)) \\ (0+(1)/(3)\cdot3,3+(1)/(3)\cdot6) \\ (1,5) \end{gathered}`