Question

What is the area of a sector with a central angle of 45 ° and a radius of 5?

Answer 1

Step 1:

In this question, we are given the following:

What is the area of a sector with a central angle of 45 ° and a radius of 5?

Step 2;

The details of the solution are as follows:

`Area\text{ of a sector = }(\theta)/(360^0)\text{ x }\pi\text{ r}^2`
`\begin{gathered} where\text{ }\theta\text{ = 45}^0,\text{ } \\ \text{and the Radius = 5} \\ Then,\text{ the area of the sector =} \end{gathered}`
`\begin{gathered} =(45^0)/(360^0)\text{ x }\pi(5)^2 \\ =\text{ }(1)/(8)\text{ x 25}\pi^ \\ =\text{ }(25\pi^)/(8)\text{ \lparen OPTION A \rparen} \end{gathered}`