Answer:
Number of ways that the representative can be chosen = 12
Step-by-step explanation:
The number of women = 2
The number of men = 3
Since the president must be a woman
Number of ways of choosing the president = 2C1
![\begin{gathered} 2C1=\text{ }(2!)/((2-1)!1!) \\ 2C1=2 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/4cnjf9bdlzem7qykshgelxkgog14e3cjwt.png)
Number of ways of choosing the president = 2
The secretary and treasurer must be men
Let us first choose the secretary out of all the three men
Number of ways of choosing the secretary = 3C1
![\begin{gathered} 3C1=\text{ }(3!)/((3-1)!1!) \\ 3C1=\text{ }(3!)/(2!) \\ 3C1\text{ = }(3*2*1)/(2*1) \\ 3C1=\text{ 3} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/i62g4p647ae98hwhqr0ehsxy6t478z4vct.png)
Number of ways of choosing the secretary = 3
After the secretary has been selected, there are 2 men left
Number of ways of selecting the treasurer = 2C1
Number of ways of choosing the treasurer = 2
Number of ways that the representative can be chosen = 2 x 3 x 2
Number of ways that the representative can be chosen = 12