Answer:
only 3, A with B B with C and A with C, but if you can use the same 2 if reversed it would be 6, for it would be A with B, B with A, C with B, B with C, A with C, and C with A.
Explanation:
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3
We can choose three ways:AB, AC, BC, as the order is not important.
Or you can calculate 3C2=(3×2)/(1×2)=3
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