Question

6 >= 3p + 9I need help

Answer 1

Given the following inequality:

`6\ge3p+9`

to solve for 'p', first we can substract 9 from both sides to get:

`\begin{gathered} 6-9\ge3p+9-9 \\ \Rightarrow-3\ge3p \end{gathered}`

now, we can divide both sides by 3 to get the solution set for p. Notice that since we are dividing by a positive number, the orientation of the inequality sign will remain the same:

`\begin{gathered} (-3\ge3p)\cdot(1)/(3) \\ \Rightarrow-(3)/(3)\ge p \\ \Rightarrow p\le-1 \end{gathered}`

therefore, p <= -1

The graph of the solution would be the following: