Question

If a is a solution of the equation below and a > 0, what is the value of a? x^2+x-12=0

Answer 1

a > 0

Find a,

x^2+x-12=0 , this equation have 2 solutions

Then

a = -1/2 + √(1 + 4•12)/2

Find 2 numbers which product is -12

And addition is a + b = -1

Both numbers are

a = 3

b= -4

Choose positive solution

THEN ANSWER IS

a= 3