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Evaluate the expression when a=1/4 and b=6. 16a
16a {}^(2) - 4b

User Msgmaxim
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Let's begin by listing out the information given to us:


\begin{gathered} a=(1)/(4),b=6.16a \\ 16a^2-4b \\ \text{Substitute the values of a and b into the expression, we have:} \\ 16a^2-4b=16a^2-4(6.16a)=16\cdot((1)/(4))^2-4(6.16a) \\ 16\cdot(1)/(16)-4(6.16\cdot(1)/(4))=1-6.16=-5.16 \\ \Rightarrow-5.16 \end{gathered}

User Seamus James
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