Question

Using the balanced equation below,how many grams of sodium bromidewould be produced from thecomplete reaction of 41.3 g AgBr?AgBr + 2Na2S2O3 → Na3Ag(S203)2 + NaBr

Answer 1

First, we write our reaction and then we balance it:

AgBr + 2Na2S2O3 → Na3Ag(S203)2 + NaBr

To solve this, we need the molar masses of AgBr and NaBr (Please, use the periodic table to do this)

The molar mass of AgBr = 188 g/mol

The molar mass of NaBr = 103 g/mol

Procedure:

188 g AgBr --------------------- 103 g NaBr

41.3 g AgBr --------------------- X

X = 22.6 g

Answer: 22.6 g NaBr can be produced