We have the following equation

Since

So, we can rewrite our equation as

Then, the vertex form of our equation is:

The graph of this equation is:
The general vertex form of a quadratic equatio is:

By comparing this equation with our result, the vertex is:

From the general vertex form, we know that the axis of symmtry is given by

so, our axis of symmetry is x= -4.
The x-intercept ocurr at f(x)=0. Then, by subsituting this value into our function, we have

which leads to
![\begin{gathered} (x+4)^2=3 \\ x+4=\pm\sqrt[]{3} \\ x=-4\pm\sqrt[]{3} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/9qaidq418g5pyw0dz6gnwpap6rb1w15ta6.png)
which gives us two x-intercepts:
![\begin{gathered} x\text{ - intercept (small value) :} \\ x=-4-\sqrt[]{3} \\ x\text{ - intercept (large value value) :} \\ x=-4+\sqrt[]{3} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/lp3118udymi976yrrf0xcpwcfed6qvov1c.png)