Question

Find the midpoint of AB for: A(7,0)|and B(0,3)​

Answer 1

`\boxed {\boxed {\sf (\frac {7}{2}, (3)/(2)) \ or \ (3,5, 1.5) }}`

Explanation:

The midpoint is essentially a point with the average of the 2 x-coordinates and the 2 y-coordinates.

The formula is:

`(\frac {x_1+x_2}{2}, (y_1+y_2)/(2))`

We are given two points: A (7,0) and B (0, 3). Remember points are written as (x, y).

Therefore,

`x_1= 7 \\y_1=0 \\x_2=0 \\x_2=3`

Substitute the values into the formula.

`(\frac {7+0}{2}, (0+3)/(2))`

Solve the numerators first.

`(\frac {7}{2}, (3)/(2))`

The midpoint can be left like this because the fractions are reduced, but it can be written as decimals too.

`(3.5, 1.5)`