Question

Hi! Please determine the mass in grams of 1.6 x 10^-3 mol glucose

Answer 1

The mass of 1.6 x 10^-3 mol glucose is calculated by multiplying the number of moles by the molar mass of glucose, which gives 0.28825 g, and is rounded to 0.288 g based on significant figures.

Step-by-step explanation:

To determine the mass in grams of 1.6 x 10-3 mol glucose, we need to calculate it using the molar mass of glucose. The molar mass of glucose (C6H12O6) can be calculated as follows:

• C (carbon): 12.01 g/mol x 6 = 72.06 g/mol
• H (hydrogen): 1.008 g/mol x 12 = 12.096 g/mol
• O (oxygen): 16.00 g/mol x 6 = 96.00 g/mol

Adding these masses gives us: 72.06 + 12.096 + 96.00 = 180.156 g/mol for glucose. We then convert the number of moles of glucose to the required mass:

Molar mass of glucose = 180.156 g/mol
Moles of glucose = 1.6 x 10-3 mol

To find the mass:

Mass = Molar mass x Number of moles
Mass = 180.156 g/mol x 1.6 x 10-3 mol
Mass = 0.28825 g

This mass would typically be rounded according to the significant figures present in the original quantity of moles provided. In this case, 0.288 g would be the appropriate mass, rounded to three significant figures.

Answer 2

Given moles , n = of 1.6 x 10^-3 mol glucose,

• molar mass of glucose( C6H1206), m= ( 6*12) + (12*1) + (6*16) = 180g/mol

,

• n = mass/Molecular Mass of glucose

,

• where n = number of moles

,

• m = n* M

mass = 1.6x10^-3 moles * 180g/mol

mass = 0.288g

• Hence mass of glucose in gram is 0.288,