Given the spinner that goes from 1 to 8, you can identify that the total number in the spinner is:
![TotalNumbers=8\text{ }](https://img.qammunity.org/2023/formulas/mathematics/college/qewhn0fx17y1b4dsoq15rj03idvdvp28jk.png)
a. By definition, Odds Numbers are those numbers that are not divisible by 2.
In this case, you can identify that the Odd Numbers the spinner has are:
![1,3,5,7](https://img.qammunity.org/2023/formulas/mathematics/college/klrz7fhmnbpj9pplow41voljhkgurbv1x7.png)
Knowing that there are four Odd Numbers, you can determine that:
![P(odds)=(4)/(8)](https://img.qammunity.org/2023/formulas/mathematics/college/gpt0t271943by7q2inzc03o8tfne20vm1n.png)
![P(odds)=(1)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/499afbhnkxd4vzqa5b4svfvlu27ng10ppi.png)
b. By definition, Even Numbers are divisible by 2.
In this case, you can identify that the Even Numbers in the spinner are:
![2,4,6,8](https://img.qammunity.org/2023/formulas/mathematics/college/7nvo35uuowyx4al0xs5igkuo4ct6hb6tgm.png)
Knowing that there are four Even Numbers, you get:
![P(evens)=(4)/(8)](https://img.qammunity.org/2023/formulas/mathematics/college/y5met2yds7632yj7b1ggr9dundh0ptee3d.png)
![P(evens)=(1)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/xwrmxzzv7a63tqny4hv8qfj8wspothqtt1.png)
c. Since there is only one number 3:
![P(3)=(1)/(8)](https://img.qammunity.org/2023/formulas/mathematics/college/scticxh0pqbb4qg6osnblg66te6ibocme7.png)
d. By definition:
![P(A\text{ or}B)=P(A)+P(B)](https://img.qammunity.org/2023/formulas/mathematics/college/oo8dm6lrp29b2bw21nnqkz3cu73f2m61nm.png)
Then:
![P(4\text{ or }6)=P(4)+P(6)](https://img.qammunity.org/2023/formulas/mathematics/college/r45la3l39gzz78j6qpaai6zj9721hd1z5j.png)
Since there is only one number 4 and only one number 6:
![P(4)=P(6)=(1)/(8)](https://img.qammunity.org/2023/formulas/mathematics/college/pufwae5z0weoah530oz9bjcj4o2dxoata4.png)
Therefore:
![P(4\text{ or }6)=(1)/(8)+(1)/(8)](https://img.qammunity.org/2023/formulas/mathematics/college/il16ufq8cgcdj58ghgstrxnkva3k3uubk6.png)
![P(4\text{ or }6)=(2)/(8)](https://img.qammunity.org/2023/formulas/mathematics/college/xvklw6viafdyxojc9fz3pu3gcj2dj5525l.png)
![P(4\text{ or }6)=(1)/(4)](https://img.qammunity.org/2023/formulas/mathematics/college/snu0sz27uhf26zctw22uq87ck1nu9fes92.png)
e. Since there is only one number 7:
![P(7)=(1)/(8)](https://img.qammunity.org/2023/formulas/mathematics/college/d814y6yht2wysym9w514drq5migzndulvw.png)
f. Knowing that there is only one number 1:
![P(1)=(1)/(8)](https://img.qammunity.org/2023/formulas/mathematics/college/d3qtgharvj29gcbfzn2hf11wuyjqvgefs0.png)
Hence, the answers are:
a.
![P(odds)=(1)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/499afbhnkxd4vzqa5b4svfvlu27ng10ppi.png)
b.
![P(evens)=(1)/(2)](https://img.qammunity.org/2023/formulas/mathematics/college/xwrmxzzv7a63tqny4hv8qfj8wspothqtt1.png)
c.
![P(3)=(1)/(8)](https://img.qammunity.org/2023/formulas/mathematics/college/scticxh0pqbb4qg6osnblg66te6ibocme7.png)
d.
![P(4\text{ or }6)=(1)/(4)](https://img.qammunity.org/2023/formulas/mathematics/college/snu0sz27uhf26zctw22uq87ck1nu9fes92.png)
e.
![P(7)=(1)/(8)](https://img.qammunity.org/2023/formulas/mathematics/college/d814y6yht2wysym9w514drq5migzndulvw.png)
f.
![P(1)=(1)/(8)](https://img.qammunity.org/2023/formulas/mathematics/college/d3qtgharvj29gcbfzn2hf11wuyjqvgefs0.png)