Question

A gas occupies 5.0 cubic meters at a temperature of 600. K. If the temperature is lowered to 300. K at constant pressure, the new volume occupied by the gas will be:

Answer 1

`V_2=2.5m^3`

Step-by-step explanation:

Hello!

In this case, according to the Charles' law as a directly proportional relationship between volume and temperature:

`(V_2)/(T_2)=(V_1)/(T_1)`

Thus, in order to compute the final volume, V2, we obtain the following expression:

`V_2=(V_1T_2)/(T_1)\\\\V_2=(5m^3*300K)/(600K)\\\\V_2=2.5m^3`

Best regards!