Given:
The radioactive substances uranium-240 has a half-life of 14 hours. The amount A(t) of a sample of uranium-240 remaining (in grams ) after t hours is given by the following exponential function:
![A(t)=5600*((1)/(2))^{(t)/(14)}](https://img.qammunity.org/2023/formulas/mathematics/college/heskdms47ydtcgctj6u2a7we0hp08ii8zj.png)
To know:
Find the initial amount in the sample and the amount remaining after 30 hours.
Step-by-step explanation:
Initial amount will be at t =0 and at t = ti time.
Solution:
We will take function A(t), at t=0 initial amount
![\begin{gathered} A(t)=5600((1)/(2))^{(t)/(14)} \\ A(0)=5600*1 \\ A(0)=5600 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/4r6ho2emlol8vnu5rnw030nn4yr6botzxs.png)
And at t = 30 hours
![\begin{gathered} A(30)=5600*((1)/(2))^{(30)/(14)} \\ =1267.89 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/wbebfv0ym6l3npryhpdz2ry65c0jqo9g4z.png)
Hence, 1267.89 gram is the answer.