Answer:
The gradient = 1.4
The linear equation is y = 1.4x
Step-by-step explanation:
Since the line passes through the origin, the two points that can be identified on the line are (0, 0) and (5, 7)
where x₁ = 0, y₁ = 0, x₂ = 5, y₂ = 7
Find the gradient using the formula:
![m\text{ = }(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/sukh4lu5s7fgiz5v423o6usjd9gul4kfrj.png)
Substitute x₁ = 0, y₁ = 0, x₂ = 5, y₂ = 7 into the formula above
![\begin{gathered} m\text{ = }(7-0)/(5-0) \\ m\text{ = }(7)/(5) \\ m\text{ = }1.4 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/8fsycdkqfx79pqfmd4tdn7fhdfd2r96i9k.png)
The point-slope form of the equation of a line is:
![y-y_1=m(x-x_1)](https://img.qammunity.org/2023/formulas/mathematics/high-school/csobd57zth7rh9k4hz9amldzpq2owf0z4j.png)
Substitute m = 1.4, x₁ = 0, y₁ = 0 into the equation above
![\begin{gathered} y-0=1.4(x-0) \\ y=1.4x \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/dlmchvteq3dcw99xe0neiuj62n5qyvgi8u.png)
The gradient = 1.4
The linear equation is y = 1.4x