Solve the following problem. Be sure to show all steps (V.E.S.T.) and work in order to receive full credit

Question

asked Jul 7, 2023 224k views

1 Answer

Justin Li · Answer 1 · 2023-07-13T17:14:06+0000

$\begin{gathered} \text{Let:} \\ x=\text{First number} \\ y=\text{Sencond number} \\ z=\text{Third number} \\ x+y+z=26 \end{gathered}$

The second number is twice than the first, so:

The third number is 6 more than the second, so:

Replacing the data into the equation:

$\begin{gathered} x+2x+2x+6=26 \\ 5x+6=26 \\ \text{Solving for x:} \\ 5x=26-6 \\ 5x=20 \\ x=(20)/(5) \\ x=4 \end{gathered}$

And:

$\begin{gathered} y=2(4)=8 \\ z=2(4)+6=8+6=14 \\ 4+8+14=26 \\ \text{Which is correct} \end{gathered}$