Step-by-step explanation
The question indicates we should use a logistic model to estimate the number of plants after 5 months.
This can be done using the formula below;

Workings
Step 1: We would need to get the value of A using the carrying capacity and initial plants that started growing in the yard.
This gives;

Step 2: Substitute the value of A into the formula.

Step 3: Find the value of the constant k
Kindly recall that we are told that the plants increase by 80% after each month. Therefore, after one month we would have;

We can then have that after t= 1month

Step 4: Substitute -k back into the initial formula.

The above model is can be used to find the population at any time in the future.
Therefore after 5 months, we can estimate the model to be;

Answer: The estimated number of plants after 5 months is 130 plants.