Given
Deck that consists of 52 cards from which 2 red cards are removed and also 7 removed which are not red
so , remaining cards are 52 - 9 = 43
Find
Probability that first card is chosen is red and second card chosen is not red.
Step-by-step explanation
Probability of chosen red card = total red cards / total cards
so ,

now remaining cards are 42
probability of chosen which is not red =

so , the probability that first card is chosen is red and second card chosen is not red =

Final Answer
Therefore , the correct option is 2