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3r^2+27
3r { +}^(2) + 27 = 0

User Illvm
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Solution

For this case we have the following:


3r^2+27=0

We can subtract 27 in both sides and we got:


3r^2=-27

Then we can divide both sides by 3 and we got:


r^2=-9

Then the possible to solution are:


r=3i,r=-3i

User Jdbertron
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