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If a gas has pressure of 398 atm and a temp of 602 k and the temp changes to 503 what is the new pressure ?

If a gas has pressure of 398 atm and a temp of 602 k and the temp changes to 503 what-example-1
User Elyana
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1 Answer

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answer and explanation

we are given initial temperature and pressure of a gas and a final temperature and we are asked to determine the final pressure

to find this we can use Boyle's law

P1/T1 = P2/T2

we can rearrange to make P2 subject of the formula

P2 = P1T2/T1

= (398 x 602)/503

= 476.3 atm

User Web  Hopeful
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