Question

In kite JKLM, m JMN = 25°. Find m angle NJM

Answer 1

From the diagram, the needed part is the right-angled triangle

`\begin{gathered} 25^0+<\text{NJM}+90^0=180^0 \\ <\text{NJM}+115^0=180^0 \\ <\text{NJM}=180^0-115^0=65^0 \\ <\text{NJM}=65^0 \end{gathered}`[tex]\begin{gathered} \text{Therefore, } \\ Hence, the answer has been deduced above.