Question

I need help with this practice problem solving Make sure to read the instructions

Answer 1

First, we can find the value of the angle theta using the trigonometric function tangent:

`\begin{gathered} \tan\theta=(y)/(x)=(2√(3))/(-2)=-√(3) \\ \Rightarrow\theta=\tan^(-1)(-√(3))=-(\pi)/(3)\cong(5)/(3)\pi \end{gathered}`

for r, we can use the following expression:

`r=√(x²+y²)`

then, in this case we have the following:

`r=\sqrt{(-2)²+(2√(3))}=√(4+4(3))=√(4+12)=√(16)=4`

therefore, the polar coordinates are (r,theta) = (4,5/3 pi)