Question

solve for x and show your steps. Is the solution extraneous? Check your work to show how you determined is the solution is extraneous or not. sqre rt.3x+12=9

Answer 1

Given:

`\sqrt[]{3x+12}=9`

Sol:.

`\begin{gathered} \sqrt[]{3x+12}=9 \\ \text{Square both side} \\ 3x+12=81 \\ 3x=81-12 \\ 3x=69 \\ x=(69)/(3) \\ x=23 \end{gathered}`

It is a not extraneous sol.