Question

If the function is
`f(x) = x {}^(2) + 2`has a domain {0,3,6,9}, what is the to range?

Answer 1

`f(x)=x^2+2`

The domain = {0, 3, 6, 9)

The domain is the values of x, then

Substitute x by 0, 3, 6, 9 to find the values of y

The rang is the set of values of y

x = 0

`f(0)=(0)^2+2=0+2=2`

y = 2

x = 3

`f(3)=(3)^2+2=9+2=11`

y = 11

x = 6

`f(6)=(6)^2+2=36+2=38`

y = 38

x = 9

`f(9)=(9)^2+2=81+2=83`

y = 83

The range = {2, 11, 38, 83}

The answer is (1)