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3 votes
If the function is
f(x) = x {}^(2) + 2has a domain {0,3,6,9}, what is the to range?

1 Answer

5 votes

f(x)=x^2+2

The domain = {0, 3, 6, 9)

The domain is the values of x, then

Substitute x by 0, 3, 6, 9 to find the values of y

The rang is the set of values of y

x = 0


f(0)=(0)^2+2=0+2=2

y = 2

x = 3


f(3)=(3)^2+2=9+2=11

y = 11

x = 6


f(6)=(6)^2+2=36+2=38

y = 38

x = 9


f(9)=(9)^2+2=81+2=83

y = 83

The range = {2, 11, 38, 83}

The answer is (1)

User Bogdan Kobylynskyi
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