we have the system of equations
6y + 2x = 3 ------> equation 1
2x + y = 8 -----> equation 2
Solve by substitution
step 1
isolate variable y in equation 2
y=-2x+8
step 2
substitute equation 2 in equation 1
6(-2x+8)+2x=3
solve for x
-12x+48+2x=3
12x-2x=48-3
10x=45
x=4.5
Find out the value of y
y=-2x+8
y=-2(4.5)+8
y=-1
the solution is the point (4.5,-1)