This is a stoichiometry problem, where we have an initial amount of reactant and we need to find out how much of the product will we end up with, in order to do that we need to:
1. Set up the properly balanced equation,
C6H12O6 + 6 O2 -> 6 CO2 + 6 H2O
2. See how many moles of reactant there are in the given amount of grams, we have 1000 grams, the molar mass of glucose is 180.16g/mol
180.16g = 1 mol
1000g = x moles
180.16x = 1000
x = 1000/180.16
x = 5.55 moles of glucose in 1000 grams
3. Check the molar ratio between the two compounds, as we can see from the balanced equation, the molar ratio is 1:6, 1 mole of glucose to produce 6 moles of CO2, therefore if we have 5.55 moles of glucose:
1 C6H12O6 = 6 CO2
5.55 C6H12O6 = x CO2
x = 33.3 moles of CO2
4. Calculate how many grams will be equal to the number of moles that we found out, the number of moles is 33.3 moles, and the molar mass of CO2 is 44.01g/mol
44.01g = 1 mol
x grams = 33.3 moles of CO2
x = 33.3 * 44.01
x = 1465.5 grams of CO2 are produced