Question

What is the spring constant for a spring that stretches by 27 cm when a load of 200 N is suspended from it?1) 0.135 N/m2) 54 N/m3) 740 N/m4) 7.4 N/m

Answer 1

Given data:

Force;

`F=200\text{ N}`

Stretching;

`\begin{gathered} x=27\text{ cm} \\ =0.27\text{ m} \end{gathered}`

The force is given as,

`F=kx`

Here, k is the force constant.

The expression for the force constant is given as,

`k=(F)/(x)`

Substituting all known values,

`\begin{gathered} k=\frac{200\text{ N}}{0.27\text{ m}} \\ =740.74\text{ N/m} \end{gathered}`

Therefore, the force constant of the spring is 740.74 N/m. Hence, option (3); 740 N/m is the best choice.