Question

In the diagram, parallel lines a and m are cut by transversal t m <1=4x + 16 and m<2 =2x - 22

Answer 1

In thia problem we have that

m<1 and m< 2 are consecutive interior angles

that means

m<1+m<2=180 ------> supplementary angles

substitute the given values

4x+16+2x-22=180

solve for x

6x-6=180

6x=180+6

6x=186

x=31

Find the value of m<1

m<1=4(31)+16

m<1=140 degrees