Question

Find the approximate surface area of each right regular prism

Answer 1

- The area of a regular pentagonal prism is given by the formula:

`\begin{gathered} A=5ah+(a^2)/(4)\sqrt{5(5+2√(5))} \\ \\ where, \\ a=base \\ h=height \end{gathered}`

- The area of a regular hexagonal prism is given by:

`\begin{gathered} A=6ah+3√(3)a^2 \\ where, \\ a=base \\ h=height \end{gathered}`

Question 1:

`\begin{gathered} a=6,h=11 \\ \\ A=5(6)(11)+(6^2)/(4)\sqrt{5(5+2√(5))} \\ \\ A=453.87437...\approx454units^2 \end{gathered}`

Question 2:

`\begin{gathered} a=2,b=9 \\ A=6(2)(9)+3√(3)(2)^2 \\ \\ A=128.78461...\approx129unit^2 \end{gathered}`

The answers are: