255,552 views
11 votes
11 votes
A train leaves at 15:43 and arrives at 17:13. It travelled at an average speed of 75 km/h.

How far did it travel? Give your answer in km to 1DP.

User Geo Angelopoulos
by
3.0k points

2 Answers

21 votes
21 votes

Answer:

112.5 km

Explanation:

The time it traveled is:

17:13 - 15:43 = 16:73 - 15:43 = 1:30

It traveled 1:30, or 1 hour and 30 minutes, or 1.5 hours.

speed = distance/time

distance = speed × time

distance = 75 km/h × 1.5 h

distance = 112.5 km

User Naval Hasan
by
3.4k points
16 votes
16 votes

Answer:

112.5 km

Explanation:

Since we are given a speed per hour, let's start with finding how much time it took for the train to travel its distance.

2 hours from 15:43 would end the journey at 17:43, and 17:13 is half an hour less than that. Therefore, the total time is 2 hours - 30 minutes = 1.5 hours.

Now that we know the time, we can set up a ratio to find the distance using the speed.

75 km/1 hour = x km/1.5 hours

To solve this equation for x (distance), we will cross multiply, giving:

75(1.5) = x(1)

x = 112.5 km

Hope this helped!

User Cow
by
2.8k points
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