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A marble with a mass of 1. 5 grams rolls at a constant rate of 0. 50 cm/s across a table. What is the magnitude of the marble's momentum?.

User MrUpsidown
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2 Answers

7 votes
7 votes

Answer: 7.5 × 10⁻⁶ kgm/s.

Step-by-step explanation:

Data:

Mass = 1.5 g => 0.0015 kg

Velocity = 0.5 cm/s => 0.005 m/s

Momentum = ?

Formula:

Momentum = Mass × Velocity

P =mv

Solution:

Momentum = 0.0015 kg × 0.005 m/s

Momentum = 0.0000075 kgm/s => 7.5 × 10⁻⁶ kgm/s

Answer:

The magnitude of the marble's Momentum is 7.5 × 10⁻⁶ kgm/s.

User Pramod Sivadas
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2.7k points
13 votes
13 votes

Answer:

Step-by-step explanation:

The momentum can be calculated as follows:

p = mv

Where m is the mass of the marble and v its velocity. Therefore:

p = 0.0015kg · 0.0005m/s = 0.0000075 kg·m/s = 7,5·10^{-6}kg·m/s

Note that we have converted the grams in kg and cm/s in m/s.

User Lior Iluz
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3.1k points