The endpoints of PQ are at P (-4. -2) and Q (6,3). What are the coordinates of point S which divides PQ such that PS : SQ is equal to 3:2?
(0,0)
(1,0.5)
(2.1)
step 1
Find the distance PQ in the x-coordinate
PQx=6-(-4)=10 units
PS/SQ=3/2
if the length is 10 units
so
PS/SQ=6/4
the x-coordinate of S is 6 units at right of P
Sx=-4+6=2
step 2
Find the distance PQ in the y-coordinate
PQy=3-(-2)=5
PS/SQ=3/2
so
the y-coordinate of S is 3 units up of point P
Sy=-2+3=1
therefore
point S(2,1)