We must find an equation for the line that passes through the points:
• A = (xA,yA) = (7,6),
,
• B = (xB,yB) = (-2,-3).
The general slope-intercept equation of a line is:
![y=m\cdot x+b,](https://img.qammunity.org/2023/formulas/mathematics/college/33ckuf2xc45slqrrwdinw3muj21bo8230n.png)
where m is the slope and b is the y-intercept of the line.
1) We can compute the slope m with the coordinates of two points of the line and the following formula:
![m=\frac{y_B-y_A}{x_B-x_A_{}},](https://img.qammunity.org/2023/formulas/mathematics/college/pumg8jg6fwh85bodbnuq4ce8etb9iumi2w.png)
where (xA,yA) and (xB,yB) are the coordinates of the points A and B, respectively.
Replacing the coordinates of the points in the formula above, we get:
![m=(-3-6)/(-2-7)=1.](https://img.qammunity.org/2023/formulas/mathematics/college/nw1gaeftcimcw1596hk0f5nkt1k0cq11qq.png)
2) To find the y-intercept b we replace the coordinate of one of the points (A for example) and the value of m = 1 in the general equation of the line, and then we solve for b:
![\begin{gathered} y_A=m\cdot x_A+b, \\ 6=1\cdot7+b, \\ b=6-7, \\ b=-1. \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/vbg3kctopq8tme8c9ehtgi0b0s52yni3du.png)
Using the values m = 1 and b = -1, we find that the equation of the line is:
![y=x-1](https://img.qammunity.org/2023/formulas/mathematics/high-school/xcmng1iqk9u8pkd9dc5p5632d1z1qni53d.png)
Answer
The equation of the line is
![y=x-1](https://img.qammunity.org/2023/formulas/mathematics/high-school/xcmng1iqk9u8pkd9dc5p5632d1z1qni53d.png)