We want to factor the expression;

This can by the normal quadratic factorization because the expression even though a
quartic, is quadratic in x^2. Let's simplify it;

Let us multiply both the constant term and the second power term to obtain

Let us think of numbers that multiply to give this number and also add to give,

The two numbers are;

Let's recast the equation then;

We can factorize one of the terms further as it is a difference of two squares.

Thus, our final answer is Eoption A