Question

Please help me with math!?!?!

Answer 1

y=1

x=3

Step by step explanation

Multiply eqn 1 by 4 and eqn 2 by 3

-12x+32y=-4

-12x+21y=-15

subtract eqn 1" from eqn 2"

11y=11

y=1

substitute y=1 into eqn 1

-3x+8(1)=-1

-3x+8=1

-3x=-8-1

-3x=-9

x=-9/-3

x=3

Answer 2

x = 3

y = 1

Explanation:

1. First step is to identify which strategy you will use to solve this system of equations: I will use Elimination to solve this system of equation:

2. We need to that can isolate x or y, I have identified and we can multiply the top by -4 and bottom equation by 3.

We get:

`\left \{ {{-3x+8y=-1} \atop {-4x+7y=-5}} \right.`

Let’s add our factors in and eliminat the x’s:

`\left \{ {{-4(-3x+8y=-1)} \atop {3(-4x+7y=-5)}} \right.`

Now let’s factor the numbers through the equation and add the equations together:

`\left \{ {{12x-32y=4} \atop {-12x+21y=-15}} \right.`

Let’s add:

…and we get

`-11y=-11`

`y = 1`

We know that y = 1 so we can subsitute and figure out x:

`-3x+8=-1`

As you can see I have taken the firsth equation and substituted y = 1: Let’s find x:

`-3x=-9`

`x = 3`

x = 3 and y = 1