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How much pressure is applied to the grand by an 80 KG man who is standing on squares stilts that measures 0.0 4m answer in units of PASecond section:- What is the pressure in the pounds per square inch answer in Units of IB/IN to the power of 2

How much pressure is applied to the grand by an 80 KG man who is standing on squares-example-1

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First section:

Given data:

The mass of the man is,


m=80\text{ kg}

The side of a square slit is


s=0.04\text{ m}

The pressure can be expressed as,


\begin{gathered} P=(F)/(A) \\ =\frac{mg}{(2s)^2^{}} \end{gathered}

Here, g is the acceleration due to gravity whose value is


9.81m/s^2

Substituting the values in the above equation, we get:


\begin{gathered} P=\frac{80\text{ kg}*9.81m/s^2}{(2*0.04\text{ m})^2}(\frac{1\text{ Pa}}{1kg/ms^2}) \\ \\ =122625\text{ Pa} \end{gathered}

Thus, the pressure in Pascals is 122625 Pa.

Second section:

The pressure in pounds per square inch can be expressed as,


\begin{gathered} P=122625\text{ Pa}(\frac{0.000145lb/in^2}{1\text{ Pa}}) \\ =17.78lb/in^2 \end{gathered}

Thus, the pressure in pounds per square inch is


17.78lb/in^2

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