Question

Given f(x)=-(x-2)^2-4

Answer 1

`f(x)=-(x-2)^2-4`

The vertex vertex form of the quadratic f is

`f(x)=a(x-h)^2+k`

Where

a is the coefficient of x^2

(h, k) are the coordinates of the vertex of the curve

By comparing them

h = 2 and k = -4

a) The vertex point is (2, -4)

If the coefficient of x^2 is negative, that means the graph is opened downward

b) The direction of the graph is downward

The axis of symmetry of the quadratic function is a vertical line passes through the v