Answer:
1. x = 4.5
2. x = 0.75 or x = -4.5
Step-by-step explanation:
The quadratic formula says the solutions of the equation with the form ax² + bx + c are:
![x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://img.qammunity.org/2023/formulas/mathematics/college/rxvf73usjbbwyik14knxdemoz21vfz2ufc.png)
So, if the equation is 4x² - 36x + 81, the value of each constant is
a = 4
b = -36
c = 81
Then, the solutions are
![\begin{gathered} x=\frac{-(-36)\pm\sqrt[]{(-36)^2-4(4)(81)}}{2(4)} \\ x=\frac{36\pm\sqrt[]{1296-1296}}{8} \\ x=\frac{36\pm\sqrt[]{0}}{8}=(36)/(8)=4.5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/u25qh8am56g6aqrcfzu2fbr2llb40g9a2x.png)
It means that this equation has a unique solution x = 4.5
In the same way, if we have the equation 8x² + 30x = 27, we first need to subtract 27 from both sides, so:
8x² + 30x - 27 = 27 - 27
8x² + 30x - 27 = 0
Now, we can identify the values of a, b, and c.
a = 8
b = 30
c = -27
Therefore, the solutions of the equation are
![\begin{gathered} x=\frac{-30\pm\sqrt[]{(30^2)-4(8)(-27)}}{2(8)} \\ x=\frac{-30\pm\sqrt[]{900+864}_{}}{16} \\ x=\frac{-30\pm\sqrt[]{1764}}{16} \\ x=(-30\pm42)/(16) \\ \text{ The solutions are} \\ x=(-30+42)/(16)=(12)/(16)=0.75 \\ or \\ x=(-30-42)/(16)=(-72)/(16)=-4.5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/do9c6evmjyzsoe7an18azjd6hlvlfviq8s.png)
So, the solutions for each quadratic equation are:
1. x = 4.5
2. x = 0.75 or x = -4.5