Question

A wooden box of mass 22.5Kg is pulled at uniform velocity along a street surface with a horizontal force of 35.2N. Calculate the coefficient of friction between the box and the street?

Answer 1

Given that the mass of the box, m = 22.5 Kg

A horizontal force, F = 35.2 N is applied to the wooden box.

A normal force acts upwards, whose value = mg

Here, g is the acceleration due to gravity whose value is 9.8 m/s^2

The formula to find the coefficient of friction is

`\mu=(F)/(mg)`

Substituting the values, we get

`\begin{gathered} \mu=(35.2)/(22.5*9.8) \\ =0.159 \end{gathered}`

Thus, the coefficient of friction between the box and the street is 0.159