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A certain ore yields an average of 59% iron. How much ore is needed to obtain 826 lb of iron?

User Sushanth
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1 Answer

6 votes

First, convert 59% into decimal by dividing by 100%


59\%/100\%=0.59

Next, divide 826 lb by 0.59 to get the amount of ore needed


826/0.59=1400

Therefore, you need 1400 lb of ore to get 826 lb of iron.

User Junsu Cho
by
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