Question

The question says drag the equations to the true box

Answer 1

EXPLANATION

Let's call x to the square:

The first equation is:

`(4)/(5)\cdot x=28`

We need to isolate x, how can we do it?

Multiplying both sides by 5/4:

`(4)/(5)\cdot(5)/(4)\cdot x=28\cdot(5)/(4)`

Multiplying the numerators:

`x=(140)/(4)`

Simplifying the fraction:

`x=35`

The solution is 35

In the second equation:

`(3)/(10)\cdot x=(57)/(10)`

Multiplying both sides by 10/3:

`x=(10)/(3)\cdot(57)/(10)=`

Multiplying terms:

`x=(570)/(30)`

Simplifying:

`x=19`

The solution is 19

In the third equation:

`(5)/(9)\cdot x=15`

Multiplying both sides by 9/5:

`x=(9)/(5)\cdot15`

Multiplying numerators and denominators:

`x=(135)/(5)`

Simplifying:

`x=27`

In the fourth equation:

`(3)/(16)\cdot x=(63)/(16)`

Multiplying both sides by 16/3:

`x=(63)/(16)\cdot(16)/(3)`

Multiplying terms:

`x=(1008)/(48)`

Simplifying:

`x=21`

The solution is 21