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5 votes
Q bisects PR. If PR = 28, and PQ= 2x+5, what is the value of x?

User Goto
by
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1 Answer

2 votes

ANSWER:

x = 4.5

Step-by-step explanation:

Since Q bisects PR, it means that Q divides the line PR exactly by half.

This means PQ = QR

Given:

PR = 28

PQ = 2x + 5

To find x, we have:


\begin{gathered} (28)/(2)=2x\text{ + 5} \\ \\ 14\text{ = 2x + 5} \end{gathered}

Solve for x:

Subtract 5 from both sides:


\begin{gathered} 14\text{ - 5 = 2x + 5 - 5} \\ \\ 9\text{ = 2x} \end{gathered}

Divide both sides by 2:


\begin{gathered} (9)/(2)\text{ = }(2x)/(2) \\ \\ 4.5\text{ = x} \end{gathered}

x = 4.5

User Hejdav
by
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