Compounded interest
Compounded interest takes into account all the accumulated interest of previous periods.
We have that it is the described by the following formula:
![A=P(1+(r)/(n))^(nt)](https://img.qammunity.org/2023/formulas/mathematics/high-school/39foo2gerf9tf1ffk32zwshrn339mz02kv.png)
where,
A = the future value of the investment, including interest
P = the initial investment amount
r = the annual interest rate (decimal)
n = the number of times that interest is compounded per year
t = the time the money is invested
In this question:
A = what we want to find
P = 35,000
r = 0.06 (since it is 6%, we divide 6/100 = 0.006)
n = 1 (since it is per annum)
t = 3 (since we want to find it after 3 years)
Now, we replace in our formula:
![\begin{gathered} A=P(1+(r)/(n))^(nt) \\ \downarrow \\ A=35,000(1+(0.06)/(1))^(1\cdot3) \\ \downarrow \\ A=35,000(1+0.06)^3 \\ A=35,000(1.06)^3 \\ \downarrow \\ (1.06)^3\approx1.191 \\ A\approx35,000\cdot1.191 \\ A\approx41,685 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/gcsjxjrr8siuy1cvqic1qyj6iaer7wmusk.png)
Answer: 4