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43 votes
43 votes
Line JK passes through points J(–3, 11) and K(1, –3). What is the equation of line JK in standard form?

7x + 2y = –1
7x + 2y = 1
14x + 4y = –1
14x + 4y = 1

User Gawin
by
3.3k points

2 Answers

18 votes
18 votes

Answer:

its b

Explanation:

User Miles Erickson
by
3.0k points
17 votes
17 votes

Answer:

7x + 2y = 1

Explanation:

Let's find the slope first. We know that slope is rise over run.

( y2 - y1 ) ÷ ( x2 - x1 ) or ( -3 - 11 ) ÷ ( 1 - (-3) ) = -7/2

Let's find the y intercept next:

y = mx + b now plug in the value of K in this equation.

-3 = -7/2 ( 1 ) + b

-3 = -7/2 + b

b = 1/2

now let's write the equation again with all the values that we want:

y = -7/2x + 1/2

let's move -7/2x on the other side. So, we get:

7/2x + y = 1/2

In out answer choices we see that we have 1 instead of 1/2 so lets multiply both side by 2 to get rid of the 2 in the denominator or 1/2.

Once we do that we get:

7x + 2y = 1

User Hyperupcall
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3.5k points