Question

A sailor pulls a boat horizontally alongside a dock for 10.0 m with a rope angled at 40.0°. He uses a force of 100.0 N.643 J766 J1.00×10^3 J4.00×10^4 J

Answer 1

We have the next diagram

First we need to obtain the force in the x-axis

`Fx=F\cos (\theta)`

where F=100 and θ=40°

`F_X=100\cos (40)=76.60N`

And the use the next formula for work

`W=F\cdot d`

where F is the force, d is the distance and W is the work

in our case F=Fx and d=10

`W=76.6\cdot10=766\text{ J}`

the work he did is 766 J