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Find the midpoint of the segment between the points (17,−11) and (−14,−16)A. (31/2,5/2)B. (−3,27)C. (3,−27)D. (3/2,−27/2)

User TehK
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1 Answer

3 votes

The midpoint (x,y) of a line segment with point (x1,y1) and (x2,y2) is given below as


(x,y)=((x_1+x_2)/(2),(y_1+y_2)/(2))

Where the given values are


\begin{gathered} (17,-11) \\ x_1=17,y_1=-11 \\ (-14,-16) \\ x_2=-14,y_2=-16 \end{gathered}

By substituting the values in the formula above


\begin{gathered} (x,y)=((x_1+x_2)/(2),(y_1+y_2)/(2)) \\ (x,y)=((17+(-14))/(2),((-11+(-16))/(2)) \\ (x,y)=((17-14)/(2),(-11-16)/(2)) \\ (x,y)=((3)/(2),-(27)/(2)) \end{gathered}

Hence,

The final answer is OPTION D

User WigglyWorld
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