
1) Note that according to this equation the rocket describes a parabola when it is flying.
2) We need to know then at what instant of time the rocket is at 30 meters. So we can write out the following:
![\begin{gathered} 30=50t-5t^2 \\ 5t^2-50t+30=0 \\ (/5)5t^2-50t+30=0(/5) \\ t^2-10t+6=0 \\ t=\frac{10\pm\sqrt[]{(-10)^2-4(1)(6)}}{2(1)} \\ t_1=5+\sqrt[]{19},t_2=5-\sqrt[]{19} \\ t_1=9.36,t_2=0.64 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/e4quo53ysb6lxy74o41kxpsf1rmvl6tn05.png)
3) Thus the rocket will be at 30 meters high in 0.64 seconds and in 9.35 seconds